7. The height​ (feet) of a ball launched in the air t seconds after it is launched is given​ by: f(t)=−16t2+286t+10. Question content area bottom Part 1 The velocity of the ball at 13.2 seconds is enter your response here ​ft/sec. 8. The height​ (feet) of a ball launched in the air t seconds after it is launched is given​ by: f(t)=−16t2+279t+16. After how many seconds is the ball at a height of 220 ​feet? Question content area bottom Part 1 The ball is at a height of 220 feet after enter your response here seconds.
9. The height​ (feet) of a ball launched in the air t seconds after it is launched is given​ by: f(t)=−16t2+302t+19. Question content area bottom Part 1 After how many seconds is the ball falling at 100 feet per​ second? enter your response here sec. 10. The height​ (feet) of a ball launched in the air t seconds after it is launched is given​ by: f(t)=−16t2+211t+15. Find the height of the ball when it is falling at 100 ​ft/sec. Question content area bottom Part 1 The height is enter your response here feet.