Respuesta :
So,
[tex] \frac{x}{4} +5= \frac{x}{3} +10[/tex]
To get rid of the fractions, find the LCM of the denominators.
LCM of 4, 3 = 12
Multiply both sides by 12.
3x +60= 4x +120
Subtract 3x from both sides.
60 = x + 120
Subtract 120 from both sides.
x = -60
Check.
[tex]\frac{-60}{4} +5= \frac{-60}{3} +10[/tex]
-15 + 5 = -20 + 10
-10 = -10
This checks.
S = {-60}
[tex] \frac{x}{4} +5= \frac{x}{3} +10[/tex]
To get rid of the fractions, find the LCM of the denominators.
LCM of 4, 3 = 12
Multiply both sides by 12.
3x +60= 4x +120
Subtract 3x from both sides.
60 = x + 120
Subtract 120 from both sides.
x = -60
Check.
[tex]\frac{-60}{4} +5= \frac{-60}{3} +10[/tex]
-15 + 5 = -20 + 10
-10 = -10
This checks.
S = {-60}
x/4 + 5 = x/3 + 10
x/4 - x/3 = 10 - 5
(3x -4x)/12 = 5
-x/12 = 5
-x = 12 *5
-x = 60
x = -60.
Check:
Left Hand side, LHS:
x/4 + 5
-60/4 + 5 = -15 + 5 = 5- 15 = -10
Right Hand side, RHS:
x/3 + 10
-60/3 + 5 = -20 + 10 = 10- 20 = -10
-10 = -10
LHS = RHS
x/4 - x/3 = 10 - 5
(3x -4x)/12 = 5
-x/12 = 5
-x = 12 *5
-x = 60
x = -60.
Check:
Left Hand side, LHS:
x/4 + 5
-60/4 + 5 = -15 + 5 = 5- 15 = -10
Right Hand side, RHS:
x/3 + 10
-60/3 + 5 = -20 + 10 = 10- 20 = -10
-10 = -10
LHS = RHS