A = 480
W = x
L = 11/5*x
therefore 480 = 11/5*x*x
480 = 11/5x^2
480*5 = 11x^2
2400/11 = x^2
[tex] + or-\sqrt{2400/11} = x [/tex]
However we can't have a negative width so width is [tex] \sqrt{2400/11} [/tex]
Sub this into the length equation to find length [tex] \frac{11}{5} * \sqrt{2400/11} [/tex]
