Respuesta :
The answer is D, y+4 = -6(x+2).
Just plug the information into the point slope formula which is, y-y1 =m(x-x1).
Just plug the information into the point slope formula which is, y-y1 =m(x-x1).
The generic equation of the line is given by:
[tex]y-yo = m (x-xo) [/tex]
Where,
m: slope of the line
(xo, yo): ordered pair that belongs to the line.
We have then that the slope of the line is:
[tex]m = -6 [/tex]
The line passes through the point (-2, -4), therefore, the ordered pair is:
[tex](xo, yo) = (-2, -4) [/tex]
Substituting values we have:
[tex]y - (- 4) = - 6 (x - (- 2)) [/tex]
Rewriting we have:
[tex]y + 4 = -6 (x + 2) [/tex]
Answer:
An equation of the line that passes through the point (-2, -4) with slope -6 is:
[tex]y + 4 = -6 (x + 2)[/tex]
[tex]y-yo = m (x-xo) [/tex]
Where,
m: slope of the line
(xo, yo): ordered pair that belongs to the line.
We have then that the slope of the line is:
[tex]m = -6 [/tex]
The line passes through the point (-2, -4), therefore, the ordered pair is:
[tex](xo, yo) = (-2, -4) [/tex]
Substituting values we have:
[tex]y - (- 4) = - 6 (x - (- 2)) [/tex]
Rewriting we have:
[tex]y + 4 = -6 (x + 2) [/tex]
Answer:
An equation of the line that passes through the point (-2, -4) with slope -6 is:
[tex]y + 4 = -6 (x + 2)[/tex]