[tex] \left\{\begin{array}{ccc}y=-7x+2\\y=9x-1\end{array}\right\Rightarrow 9x-1=-7x+2\\\\9x-1=-7x+2\ \ \ |+1\\9x=-7x+3\ \ \ |+7x\\16x=3\ \ \ \ |:16\\x=\dfrac{3}{16}\\\\\text{substitute the value of x to the second equation}\\\\y=9\cdot\dfrac{3}{16}-1\\\\y=\dfrac{27}{16}-\dfrac{16}{16}\\\\y=\dfrac{11}{16}\\\\\text{The solution is}\ \left(\dfrac{3}{16};\ \dfrac{11}{16}\right) [/tex]
