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two cubes have sides of length 3 cm and 8 cm. what is the ratio of their respective surface areas?

Respuesta :

The surface area formula for a cube is: 6 * s^2, where s is the side length.

The two surface areas are:

6 * 3^2 = 54

and

6 * 8^2 = 384

The ratio of their surface areas, from the surface area of the smaller cube to the surface area of the larger cube is:

54/384 = 9/64

The answer is 9/64.

Note that another way to to find the ratio of the squares of the side lengths of the cubes.

The ratio of respective surface areas will be "[tex]\frac{9}{64}[/tex]".

Given values are:

Cube's side length,

  • [tex]a_1 = 3 \ cm[/tex]

Another cube's side length,

  • [tex]a_2 = 8 \ cm[/tex]

Now,

→ The surface area of cube will be:

= [tex]6(a_1)^2[/tex]

= [tex]6(3)^2[/tex]

= [tex]6\times 9[/tex]

= [tex]54 \ cm^2[/tex]

→ The another cube's surface area will be:

= [tex]6(a_2)^2[/tex]

= [tex]6(8)^2[/tex]

= [tex]6\times 64[/tex]

= [tex]384 \ cm^2[/tex]

hence,

The ratio of respective surface areas will be:

= [tex]\frac{6(a_1)^2}{6(a_2)^2}[/tex]

= [tex]\frac{54}{384}[/tex]

= [tex]\frac{9}{64}[/tex]

Thus the above answer is correct.

Learn more about surface area here:

https://brainly.com/question/10026601

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