The formula T= 2pi sqrt(L/32) relates the time, T, in seconds for a pendulum with the length, L, in feet, to make one full swing back and forth. What is the length of a pendulum that makes one full swing in 2.2 seconds? Use 3.14 for pi.

Respuesta :

Remark

I like to work from the original equation.

Givens

T = 2.2 seconds

pi = 3.14

L = ??

Substitute and Solve

T = 2*pi*sqrt(L/32) Find the value of 2*pi

2.2 = 2*3.14* sqrt(L/32)

2.2 = 6.28 * sqrt(L/32) Divide both sides by 6.28

2.2/6.28 = sqrt(L/32)

0.35032 = sqrt(L/32) Square both sides.

0.122723 = L/32 Multiply both sides by 32

0.122723 * 32 = L

L = 3.927 feet. <<<<< Length pendulum creating 2.2 seconds.

The length of a pendulum that makes one full swing in 2.2 seconds is 392.71 feet

Given the formula for calculating the length of the pendulum expressed as:

[tex]T = 2 \pi \sqrt{\frac{L}{32} }[/tex] where:

L is the length of the pendulum

T is the period of the pendulum

Given the following parameters:

Period T = 2.2 seconds

Substitute the given parameters into the formula will give;

[tex]2.2 = 2 \pi \sqrt{\frac{L}{32} }\\(\frac{22}{6.28})^2 =\frac{L}{32}\\ 3.5032^2 = \frac{L}{32}\\L = 3.5032^2 \times 32\\L = 392.71feet[/tex]

This shows that the length of a pendulum that makes one full swing in 2.2 seconds is 392.71 feet

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