Respuesta :
When Ag[tex]^{+}[/tex]reacts with sodium carbonate, [tex]Na_{2}CO_{3}[/tex], a white precipitate forms. The reaction between Ag[tex]^{+}[/tex]and sodium carbonate, [tex]Na_{2}CO_{3}[/tex] cna be represented as:
[tex]Ag^{+}(aq)+Na_{2}CO_{3}(aq)-->Ag_{2}CO_{3}(s)+2Na^{+}(aq)[/tex]
So when an aqueous solution containing silver ions is mixed with an aqueous solution of sodium carbonate, a white precipitate of silver carbonate is formed. This indicates that the reaction would be a precipitation reaction as the carbonate of silver is insoluble in water.
Answer:
We have [tex]Na_2CO_3[/tex] in an aqueous state
[tex]Na_2CO_3[/tex] is a salt therefore being in an aqueous state will ionize
It will separate into the two ions that compose it.
When adding silver ions in an aqueous state a simple displacement reaction will occur
[tex]Ag^{+}_{(aq)} + Na_2CO_3_{(aq)} \longrightarrow Ag_2CO_3_{(s)} +Na^+_{(aq)}[/tex]
In a simple displacement reaction, an element reacts with a compound and takes the place of one of the elements of the compound, producing a different element and also a different compound.
General equation of a simple displacement reaction
[tex]A+BC\longrightarrow AC + B[/tex]
In this case, silver displaces sodium because it is a more reactive metal.
After the reaction occurs, a precipitate of calcium carbonate is observed since this new compound is insoluble in water.