Respuesta :
Solution:
Question made by me:
As you know that there are million of microbes in air.Consider a microbe have name Sekrit whose size is equal to [tex]1.023 \times 10 ^ {-2}[/tex]. A scientist found the number of microbes on that tree equal to Avogadro's number which is [tex]6.023 \times 10 ^{23}[/tex] on that particular kind of tree. Find the total mass of microbe Sekrit that exists on that particular tree.
Solution: Total mass of microbe Sekrit that exists on particular tree= Mass of a microbe Sekrit * Total number of microbe Sekrit on that particular tree
= [tex]1.023 \times 10 ^{-2} \times 6.023 \times 10 ^{23}\\\\6.161529\times 10^{21}[/tex]
Question Made by my friend:
A new kind of Star is found in the universe . The distance of that star from the planet earth is equal to Avogadro's number which is equal to [tex]6.023 \times 10 ^{23}[/tex] . There are fifteen stars which form the pattern are equidistant from planet earth.Find the sum of total distances.
Solution: Distance of fifteen star from planet earth = [tex]6.023 \times 10 ^{23}[/tex]
Total Distance = [tex]15 \times 6.023 \times 10^{23}=90.345 \times 10^{23}=9.0345 \times 10^{23}[/tex]
The two answers are different as it describes different kinds of problems using Avogadro's number.
Answer:
In 30 grams of water there are 1.0036*10^24 molecules. Calculate Avogadro's number from these data.
Step-by-step explanation:
The molar mass of water (H2O) is:
2*molar mass of H + molar mass of O
2*1 + 16 = 18 g/mol
This means that 1 mol has a mass of 18 grams. We know that the number of molecules present in 1 mol is the Avogadro's number. From data, we can state the following proportion:
30 g of H2O / 18 g of H2O = 1*10^24 molecules / x molecules
x = 1.0036*10^24*18/30 ≈ 6.022*10^23 molecules of H2O
This number of molecules corresponds to 1 mol, then it is the Avogadro's number.
