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HELP PLEASE!!! The fourth term in an arithmetic sequence is 19 and the sixth term is 27. If the first term is a1, which is an equation for the nth term of this sequence

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wegnerkolmp2741o

Answer:

an =7+4(n-1)

Step-by-step explanation:

an =a1+ d(n-1) is the equation for an arithmetic sequence

When n=4   an =19

19 =a1 + d(4-1)

19 =a1 + d(3)

When n =6  an =27

27 = a1 +d*(6-1)

27 = a1 +d*5

Now we have 2 equations and 2 unknowns

19 =a1 + d(3)

27 = a1 +d*5

Subtract them to eliminate a1

 27 = a1 +d*5

-19 =a1 + d(3)

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8   =   2d

Divide by 2

8/2 = 2d/2

4 =d

The common difference is 4

Now we need to find  a1

 27 = a1 +d*5

27 = a1 + (4) *5

27 = a1+ 20

Subtract 20 from each side

27-20 =a1 +20-20

7 =a1

The initial term is 7

an = a1+ d(n-1)

an =7+4(n-1)

Answer:

The nth term = a1 + 4(n - 1).

Step-by-step explanation:

The  value of the 6th term - the values of the fourth =  2 * common difference (d).

So, d = 27 - 19 = 2d giving d = 8/2 = 4.

The nth term is  an = a1 + 4(n - 1).

To find the value of a1  we use the knowledge that a4 = 19

Taking 4 away from this gives us the  3rd term = 15. To get a1 we need to take another 2 4's away. This gives us 15-8 = 7.

So the nth term  = 7 + 4(n - 1).

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