Respuesta :
Step-by-step explanation:
Given:
There are 10 counters.
6 of the counters are white.
Two counters are drawn one after another without replacement.
To Find:
The probability that only one of the two counters is white
Explanation:
P(Only one of the two counters is white)
= P(white) x P( not white) + P(not white) x p(white)
Solution:
P(Only one of the two counters is white) = 6/10 x 4/9 + 4/10 x 6/9
P(Only one of the two counters is white) = 4/15 + 4/15
P(Only one of the two counters is white) = 8/15
Answer: The probability is 8/15
The probability that only one of the two counters is white will be [tex]8\div15[/tex] and this can be determined by using the probability formula.
Given :
- A bag contains 10 counters, 6 of them are white.
- The counter is taken at random and not replaced.
The probability that only one of the counters is white will be:
[tex]\rm =(probability\; of \;white\; counter) \times (probability\; of\; not \;a\; white \;counter) + (probability \;of\; not\; white\;p counter )\times (probability\; of\; white \;counter)[/tex]
[tex]= \left(\dfrac{6}{10}\times \dfrac{4}{9}\right)+\left (\dfrac{4}{10}\times \dfrac{6}{9}\right )[/tex]
[tex]= \left(\dfrac{12}{45}\right)+\left (\dfrac{4}{15}\right )[/tex]
[tex]=\dfrac{8}{15}[/tex]
Therefore, the probability that only one of the two counters is white will be[tex]8\div15[/tex].
For more information, refer to the link given below:
https://brainly.com/question/23017717
