Answer: A. 20
Step-by-step explanation:
For the general equation of ellipse :-
[tex]\dfrac{(x-h)^2}{a^2}+\dfrac{(y-k)^2}{b^2}=1[/tex]
If a > b , then the length of major axis = 2a
If b> a , then the length of major axis = 2b
The given equation : [tex]\dfrac{(x-3)^2}{49}+\dfrac{(y+6)^2}{100}=1[/tex]
Which can be written as :
[tex]\dfrac{(x-3)^2}{7^2}+\dfrac{(y+6)^2}{10^2}=1[/tex]
Here 10 >7 , then the length of major axis =2(10)=20 units
