what is the surface area of this square pyramid
Answer:
Step-by-step explanation:
We have
the square with side s = 3ft
four triangles with base b = 3ft and height h = 4ft
The formula of an area of a square:
[tex]A=s^2[/tex]
The formula of an area of a triangle:
[tex]A=\dfrac{bh}{2}[/tex]
Substitute:
[tex]A_{\square}=3^2=9\ ft^2[/tex]
[tex]A_{\triangle}=\dfrac{(3)(4)}{2}=\dfrac{12}{2}=6\ ft^2[/tex]
The Surface Area:
[tex]S.A.=A_{\square}+4A_{\triangle}\\\\S.A.=9+(4)(6)=9+24=33\ ft^2[/tex]
Answer:
33 ft&²
Step-by-step explanation:
multiply 4x3x3 = 36 and put half of 6, then it is 33 33ft²