Answer:
[tex]\boxed{\text{-272.83 }^{\circ}\text{C}}[/tex]
Explanation:
We can use the Ideal Gas Law to calculate the temperature.
pV = nRT
[tex]T = \dfrac{pV}{nR}[/tex]
Data:
p = 0.998 atm
V = 0.125 L
n = 4.75 mol
R = 0.082 06 L·atm·K⁻¹mol⁻¹
Calculation:
[tex]T = \dfrac{0.998 \times 0.125}{4.75 \times 0.082 06} =\text{0.320 K}[/tex]
T = (0.320 – 273.15) °C = -272.83 °C
Note: This is an impossible situation. CO₂ solidifies at -78.5 °C.
If CO₂ were an ideal gas, the calculated temperature would be [tex]\boxed{\text{-272.83 }^{\circ}\text{C}}.[/tex]
