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What is the exact value for the expression the square root of 56. − the square root of 14. + the square root of 126.? Simplify if possible. the square root of 14. 4 the square root of 14. 2 the square root of 42. 8 the square root of 42.

Respuesta :

[tex]\bf \sqrt{56}-\sqrt{14}+\sqrt{126}~~ \begin{cases} 56=&2\cdot 2\cdot 2\cdot 7\\ &2^2\cdot 14\\ 126=&2\cdot 3\cdot 3\cdot 7\\ &2\cdot 3^2\cdot 7\\ &3^2\cdot 14 \end{cases}\implies \sqrt{2^2\cdot 14}-\sqrt{14}+\sqrt{3^2\cdot 14} \\\\\\ \stackrel{\textit{let's add the like-terms}}{2\sqrt{14}-\sqrt{14}+3\sqrt{14}}\implies 4\sqrt{14}[/tex]

jcherry99

Answer:

Step-by-step explanation:

sqrt(56) = sqrt(4*14) = 2*sqrt(14)

sqrt(126)= sqrt(9*14) = 3*sqrt(14)

2*sqrt(14) - sqrt(14) + 3*sqrt(14)

5sqrt(14) - sqrt(14)

4*sqrt(14)

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The second one is not clear enough.

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