Answer:
[tex]\large\boxed{\dfrac{6x^2-54x}{x-9}\cdot\dfrac{7x}{6x}=7x}[/tex]
Step-by-step explanation:
[tex]\dfrac{6x^2-54x}{x-9}=\dfrac{6x(x-9)}{x-9}=6x\qquad\text{canceled}\ (x-9)\\\\\dfrac{7x}{6x}=\dfrac{7}{6}\qquad\text{canceled}\ x\\\\\dfrac{6x^2-54x}{x-9}\cdot\dfrac{7x}{6x}=6x\cdot\dfrac{7}{6}=7x\qquad\text{canceled 6}[/tex]
