Answer:
[tex]4.4285\times 10^8 [/tex] many atoms would it take to make the distance 6.20 cm from end to end.
Explanation:
Diameter of the helium atom = [tex]d=1.40\times 10^2 pm[/tex]
Let the number of atoms required to make the distance 6.20 cm be n.
[tex]d\times n= 6.20 cm =6.20\times 10^{10} pm[/tex]
[tex]1.40\times 10^2 pm\times n=6.20\times 10^{10} pm[/tex]
[tex]n=\frac{6.20\times 10^{10} pm}{1.40\times 10^2 }=4.4285\times 10^8 [/tex]
[tex]4.4285\times 10^8 [/tex] many atoms would it take to make the distance 6.20 cm from end to end.
