Answer : The solubility at [tex]25^oC[/tex] is, 0.0658 M
Explanation :
According to the Henry's Law, the solubility of a gas in a liquid is directly proportional to the pressure of the gas.
[tex]S\propto P[/tex]
or,
[tex]\frac{S_1}{S_2}=\frac{P_1}{P_2}[/tex]
where,
[tex]S_1[/tex] = initial solubility of carbon dioxide gas = 0.0347 M
[tex]S_2[/tex] = final solubility of carbon dioxide gas = ?
[tex]P_1[/tex] = initial pressure of carbon dioxide gas = 775 torr
[tex]P_2[/tex] = final pressure of carbon dioxide gas = 1470 torr
Now put all the given values in the above formula, we get the final solubility of the carbon dioxide gas.
[tex]\frac{0.0347M}{S_2}=\frac{775\text{ torr}}{1470\text{ torr}}[/tex]
[tex]S_2=0.0658M[/tex]
Therefore, the solubility at [tex]25^oC[/tex] is, 0.0658 M
