Gold has a density of 1,200 lb./ft. What is the density of gold in g/em? For conversion factors use I lb. 453.6 g, and l inch-2.54 cm. (1 f-12 inches)

Respuesta :

Answer: The density of gold in [tex]g/cm^3[/tex] is [tex]19.22g/cm^3[/tex]

Explanation:

Density is defined as the ratio of mass of the object and volume of the object. Mathematically,

[tex]\text{Density}=\frac{\text{Mass of the object}}{\text{Volume of the object}}[/tex]

We are given:

Density of gold = [tex]1200lb/ft^3[/tex]

Using conversion factors:

1 lb = 453.6 g

1 feet = 12 inches

1 inch = 2.54 cm

Converting given quantity into [tex]g/cm^3[/tex], we get:

[tex]\Rightarrow (\frac{1200lb}{ft^3})\times (\frac{453.6g}{1lb})\times (\frac{1ft}{12inch})^3\times (\frac{1inch}{2.54cm})^3\\\\\Rightarrow 19.22g/cm^3[/tex]

Hence, the density of gold in [tex]g/cm^3[/tex] is [tex]19.22g/cm^3[/tex]

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