Answer: The density of gold in [tex]g/cm^3[/tex] is [tex]19.22g/cm^3[/tex]
Explanation:
Density is defined as the ratio of mass of the object and volume of the object. Mathematically,
[tex]\text{Density}=\frac{\text{Mass of the object}}{\text{Volume of the object}}[/tex]
We are given:
Density of gold = [tex]1200lb/ft^3[/tex]
Using conversion factors:
1 lb = 453.6 g
1 feet = 12 inches
1 inch = 2.54 cm
Converting given quantity into [tex]g/cm^3[/tex], we get:
[tex]\Rightarrow (\frac{1200lb}{ft^3})\times (\frac{453.6g}{1lb})\times (\frac{1ft}{12inch})^3\times (\frac{1inch}{2.54cm})^3\\\\\Rightarrow 19.22g/cm^3[/tex]
Hence, the density of gold in [tex]g/cm^3[/tex] is [tex]19.22g/cm^3[/tex]