Answer: 18.9 calories
Explanation:
The quantity of heat required to raise the temperature of a substance by one degree Celsius is called the specific heat capacity.
[tex]Q=m\times c\times \Delta T[/tex]
Q = Heat absorbed
m= mass of substance = 1.0 g = 0.001 kg
c = specific heat capacity of aluminium = [tex]921.096J/kgK[/tex]
Initial temperature = [tex]T_i[/tex] = 847 K
Final temperature = [tex]T_f[/tex] = 933 K
Change in temperature ,[tex]\Delta T=T_f-T_i=(933-847)K=86K[/tex]
Putting in the values, we get:
[tex]Q=0.001kg\times 921.096J/kgK\times 86K[/tex]
[tex]Q=79.2J=18.9cal[/tex] (1J=0.24cal)
The number of calories required for this heat up process is 18.9 calories.
