Answer:
The p -value is less than 0.001.
Step-by-step explanation:
Given information:
Sample size = 25 chips
Sample mean = 985
Sample standard deviation = 10
Let as assume that sample is distributed normally.
The formula for test statistic
[tex]t=\frac{\overline{x}-\mu}{\frac{s}{\sqrt{n}}}[/tex]
where,
[tex]\overline{x}[/tex] is sample mean
μ is population mean.
s is sample standard deviation.
n is sample size.
The value of test statistic is
[tex]t=\frac{985-1000}{\frac{10}{\sqrt{25}}}[/tex]
[tex]t=\frac{985-1000}{\frac{10}{\sqrt{25}}}[/tex]
[tex]t=-7.5[/tex]
The p-value is
[tex]p=2\times p(t<-7.5)=2\times 0.000=0[/tex]
Therefore the p -value is less than 0.001.