Answer:
The potential difference between the plates is 8 V.
Explanation:
Given that,
Area of plates = 0.40 m²
Charge [tex]q=7.08\times10^{-10}\ C[/tex]
Distance = 4.0 cm
We need to calculate the electric field
Using for formula of electric field
[tex] E=\dfrac{2q}{2\epsilon_{0}A}[/tex]
Where, q = charge
A = area
Put the value into the formula
[tex]E=\dfrac{7.08\times10^{-10}}{8.85\times10^{-12}\times0.40}[/tex]
[tex]E=200\ V/m[/tex]
We need to calculate the potential difference between the plates
Using formula of potential difference
[tex]V=E\times d[/tex]
Where, E = electric field
d = distance
Put the value into the formula
[tex]V=200\times0.04[/tex]
[tex]V=8\ V[/tex]
Hence, The potential difference between the plates is 8 V.
