During a tensile test, a metal has a true strain = 0.08 at a true stress = 37,000 lb/in2. Later, at a true stress = 55,000 lb/in2, true strain = 0.24. Determine the strength coefficient and strain-hardening exponent in the flow curve equation.

Respuesta :

Answer:

The strength coefficient and strain-hardening exponent in the flow curve equation are 92038 and 0.3608.

Explanation:

Given that,

True stress = 37000

True strain = 0.08

Later,

True stress = 55000

True strain = 0.24

Using formula of true stress

[tex]\sigma=K\epsilon^n[/tex]

We need to make a two equation of true stress

Using formula of true stress

[tex]37000=K(0.08)^n[/tex]....(I)

[tex]55000=K(0.24)^n[/tex]....(I)

Dividing equation (II) and (I)

[tex]\dfrac{55000}{37000}=\dfrac{(0.24)^n}{(0.08)^n}[/tex]

[tex]1.4865=(\dfrac{0.24}{0.08})^n[/tex]

[tex]1.4865=3^n[/tex]

Taking ln in both side

[tex]ln(1.4865)=n ln(3)[/tex]

[tex]n=\dfrac{ln(1.4865)}{ln(3)}[/tex]

[tex]n=0.3608[/tex]

We need to calculate the value of strength coefficient

Put the value of n in equation (I)

[tex]37000=K(0.08)^(0.3608)[/tex]

[tex]K=\dfrac{37000}{0.08^{0.3608}}[/tex]

[tex]K=92038[/tex]

Hence, The strength coefficient and strain-hardening exponent in the flow curve equation are 92038 and 0.3608.

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