Answer:
V = 15.9512 dm³
Explanation:
Given data:
Pressure = P = 1.37 atm
Temperature = T= 315 K
Number of moles of nitrogen= n = 0.845 mol
Volume = V = ?
Formula:
PV = nRT
Now we will put the values in equation.
V = nRT/ P
V = ( 0.845 mol× 0.0821 dm³.atm.K⁻¹.mol⁻¹ × 315 K) / 1.37 atm
V = 21.853 dm³. atm/ 1.37 atm
V = 15.9512 dm³
Answer:
The volume occupied by 0.845 mole of nitrogen gas is 15.9 L.
Explanation:
Given
N = 0.845 mol
P = 1.37 atm
T = 315 k
We make use of the Ideal gas equation to solve this problem
Ideal gas law equation is
PV=nRT
Rearranging the formula
[tex]v= \frac {nRT}{V}[/tex]
Plugging in the values given we have
[tex]v=\frac {(0.845mol \times 0.08206 L atmk^{-1} mol^{-1} \times 315K)}{1.37atm}[/tex]
v = 15.9 L is the volume occupied by 0.845 mole of nitrogen gas.
