Find the distance from point A to XZ. round to nearest 10th!
Answer:
[tex]\large \boxed{4.1}[/tex]
Step-by-step explanation:
You want to find the length of AZ.
Create a new point W at (3, -1).
Then we can make a new right triangle AWZ in which AZ is the hypotenuse.
We can apply Pythagoras' Theorem.
[tex]\begin{array}{rcl}AX^{2} & = & AW^{2} + WZ^{2}\\& = & 4^{2} + 1^{2}\\& = & 16 + 1\\& = & 17\\AZ & = & \sqrt{17}\\& \approx & \mathbf{4.1}\\\end{array}\\\text{The distance from A to XZ is } \large \boxed{\mathbf{4.1}}[/tex]
Answer:
The AZ is perpendicular line from A to line XZ, the perpendicular distance is 4.1 units. The reason for the answer is below.
Step-by-step explanation:
Given:
A(3,3)
X(-4,-3)
Z(4,-1)
Y(2,-1.5)
To find:
The (perpendicular) distance from point A to side XZ.T
The perpendicular distance is the distance from A to Z. Let's use the distance formula.
Distance between two points (x1,y1) and (x2,y2) is
[tex]\sqrt{(y2-y1)^{2}+(x2-x1)^{2} }[/tex]
Now, for A(3,3) and Z(4,-1)
Distance = [tex]\sqrt{(-1-3)^{2} +(4-3)^{2} }[/tex]
Simplify it,
=[tex]\sqrt{(-4)^{2} +(1)^{2} }[/tex]
=[tex]\sqrt{16+1}[/tex]
=[tex]\sqrt{17}[/tex]
≈4.1 units
The distance from point A to side XZ is 4.1 units.
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https://brainly.com/question/14770442.