Respuesta :
Answer:
Explanation:
Weight, W = 286 N
Tension in the left wire, T1 = 433 N
α = 12.7°
let the tension in the right wire is T2 and angle with the horizontal is β.
Make the components and maintain the equilibrium
(a)
Equilibrium of forces along x axis
[tex]T_{2}Cos\beta = T_{1}Cos\alpha[/tex]
[tex]T_{2}Cos\beta = 433Cos12.7=422.4[/tex] .... (1)
Equilibrium of forces along y axis
[tex]T_{2}Sin\beta +T_{1}Sin\alpha = W[/tex]
[tex]T_{2}Sin\beta +433Sin12.7 = 286[/tex]
[tex]T_{2}Sin\beta=190.8[/tex] .... (2)
Squarring equation (1) and (2) and then add
[tex]\left (T_{2} \right )^{2}=422.4^{2}+190.8^{2}[/tex]
T2 = 463.5 N
(b) Divide equation (2) by (1)
[tex]tan\beta =\frac{190.8}{422.4}=0.45[/tex]
β = 24.2°
(a) T2 be the tension in right wire
Use
