Respuesta :
Answer:
a) mean = 14.83
b) mean 10.56
c) set B has a larger values of data set than A. Hence to determine the mean value of B we divide the total sum of by a larger number than for A
Step-by-step explanation:
Given data:
set A,
n = 5
x =10
set B
n = 50
x = 10
a) when 39 is addded in set A. So mean value is
[tex]mean = \frac{((5\times 10)+39)}{6}[/tex]
mean = 14.83
b). when 39 is added in set B. So mean value is
[tex] mean = \frac{((50\times 10)+39)}{51}[/tex]
mean = = 10.56
c). set B has a larger values of data set than A. Hence to determine the mean value of B we divide the total sum of by a larger number than for A.
The new mean values of the datasets are :
- SET A = 14.833
- SET B = 10.567
THE sample size of set B is larger than the sample size of set A, hence the addition of the same value to each set will have lesser effect on the mean value of the larger dataset due to larger sample size
Given the data sets :
SET A :
SET A : x = 10 ; n = 5
SET B :
SET B :x = 10 ; n = 50
Mean = ΣX/ n
ΣX = mean × n
n = sample size
Adding 39 to preexisting data and then calculate the new mean :
SET A :
ΣX = mean × n
ΣX = 10 × 5 = 50
New mean of set A :
After adding a new data POINT 39 , Sample size, n = 5 + 1 = 6
New Mean of SET A = (50 + 39) / 6 = 89 / 6 = 14.833
SET B :
ΣX = mean × n
ΣX = 10 × 50 = 500
New mean of Set B :
After adding a new data POINT 39 , Sample size, n = 50 + 1 = 51
New mean of set B = (500 + 39) / 6 = 539/51 = 10.567
THE addition of 39 to each dataset changes the mean value of SET A more than that of SET B because the sample size of set B is much larger Than that of set A.
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