Respuesta :
Explanation:
According to the Henderson Hasselbach equation,
pH = [tex]pK_{a} + log [\frac{\text{conjugate base}}{acid}][/tex]
pH = [tex]pK_{a} + log [\frac{glutamate}{\text{glutamic acid}}][/tex]
The given data is as follows.
pH = 2.5
[tex]pK_{a}[/tex] of side chain of glutamic acid = 4.1
Now, rearranging the equation as follows.
[tex]log [\frac{glutamate}{\text{glutamic acid}}][/tex] = [tex]pH - pK_{a}[/tex]
[tex]log [\frac{glutamate}{\text{glutamic acid}}][/tex] = 2.5 - 4.1
= -1.6
[tex][\frac{glutamate}{\text{glutamic acid}}][/tex] = Antilog (-1.6)
= 0.0251
or, = [tex]2.5 \times 10^{-2}[/tex]
Thus, we can conclude that the concentration ratio of the deprotonated form (glutamate) of the side chain Glu vs the protonated form (glutamic acid) in the vacuolar lumen of lemon fruit cells is [tex]2.5 \times 10^{-2}[/tex].
