A coal-burning power plant generates electrical power at a rate of 650 megawatts (MW), or 6.50 × 108 J/s. The plant has an overall efficiency of 38% for the conversion of heat to electricity. Given this efficiency, how much heat energy in joules is produced in one year of operation??

Respuesta :

Answer:

Energy produce in one year =20.49 x 10¹⁶ J/year

Explanation:

Given that

Plant produce 6.50 × 10⁸ J/s of energy.

It produce  6.50 × 10⁸ J in 1 s.

We know that

1 year = 365 days

1 days = 24 hr

1 hr = 3600 s

1 year = 365 x 24 x 3600 s

1 year = 31536000 s

So energy produce in 1 year = 31536000 x  6.50 × 10⁸ J/year

          Energy produce in one year = 204984 x 10¹² J/year

          Energy produce in one year =20.49 x 10¹⁶ J/year

In this exercise we have to use energy knowledge to calculate the energy produced in a year, this will be:

Energy produce in one year is [tex]20.49 * 10^{16} J/year[/tex]

Given the following information, we have:

  • electrical power at a rate of 650 MW
  • efficiency of 38%

So we know that for one year this will be the following account:

[tex]P=31536000 * 6.50 * 10^8 J/year\\P= 204984 * 10^{12} J/year\\P=20.49 * 10^{16} J/year[/tex]

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