Answer:
Work done, [tex]W=1.75\times 10^5\ J[/tex]
Explanation:
It is given that,
Pressure of the stream, [tex]P=1.75\times 10^6\ N/m^2[/tex]
Radius of the piston, r = 0.2 m
Distance moved by the piston, h = 0.8 m
Work done in terms of pressure is given by :
[tex]W=P\Delta V[/tex]
[tex]\Delta V[/tex] is the volume of cylinder
[tex]W=P\Delta \pi r^2 h[/tex]
[tex]W=1.75\times 10^6\times \pi 0.2^2\times 0.8[/tex]
W = 175929.18 J
or
[tex]W=1.75\times 10^5\ J[/tex]
So, the work done by the stream is [tex]1.75\times 10^5\ J[/tex]. Hence, this is the required solution.
