Answer:
The initial speed of the ball is 23.3 m/s.
Explanation:
Given that,
Angle = 44°
Range = 55.7 m
We need to calculate the initial speed of the ball
Using formula of range
[tex]R=\dfrac{u^2\sin2\theta}{g}[/tex]
Where. u = initial velocity
r = range
g = acceleration due to gravity
Put the value into the formula
[tex]55.7=\dfrac{u^2\sin2\times44}{9.8}[/tex]
[tex]u^2=\dfrac{55.7\times9.8}{\sin88}[/tex]
[tex]u=\sqrt{\dfrac{55.7\times9.8}{\sin88}}[/tex]
[tex]u=23.3\ m/s[/tex]
Hence, The initial speed of the ball is 23.3 m/s.
