The volume of 0.123 M AgNO₃ (aq) is 34.2 mL. The correct option is E.
What is volume?
Volume is the space occupied by the object. It is a scalar quantity.
The reaction is [tex]2AgNO_3(aq) + H_2SO_4(aq) \rightarrow Ag_2SO_4(s) + 2H_2O(l)[/tex]
The mole ratio of [tex]AgNO_3[/tex] to [tex]Ag_2SO_4[/tex] is 2:1
[tex]0.657 g\; Ag_2SO_4 \times \dfrac{1 mol}{312 g} = 0.00211\; mol\; Ag_2SO_4[/tex]
[tex]0.00211 mol\; Ag_2SO_4 \times \dfrac{2 mol}{1 mol } = 0.00421\; mol\; Ag_2SO_4.[/tex]
[tex]0.00421 mol\; Ag_2SO_4 \times \dfrac{1 l}{0.123 mol } = 0.0342 \; mol\; Ag_2SO_4[/tex]
0.0342 = 34.2 ml.
Thus, the required volume is 34.2 ml.
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