Answer : The product of this second decay reaction is, polonium (Po).
Explanation :
Alpha decay : In this process, alpha particles is emitted when a heavier nuclei decays into lighter nuclei. The alpha particle released has a charge of +2 units.
The general representation of alpha decay reaction is:
[tex]_Z^A\textrm{X}\rightarrow _{Z-2}^{A-4}Y+_2^4\alpha[/tex]
When radium undergoes alpha decay, the alpha decay reaction will be,
[tex]_{88}^{226}\textrm{Ra}\rightarrow _{86}^{222}\textrm{Rn}+_2^4He[/tex]
When product (radon) undergoes alpha decay, the alpha decay reaction will be,
[tex]_{86}^{222}\textrm{Rn}\rightarrow _{84}^{218}\textrm{Po}+_2^4He[/tex]
So, the element is polonium (Po) that has atomic number 84 and atomic mass 218.
Hence, the product of this second decay reaction is, polonium (Po).