Respuesta :
Answer:
The final speed become[tex] \sqrt{2}[/tex] of the initial speed .
Explanation:
We know that kinetic energy given as
[tex]K.E.=\dfrac{1}{2}mv^2[/tex]
m=mass ,v=velocity
From work power energy theorem
Work done by all forces = Change in the kinetic energy
At initial condition
[tex]W=\dfrac{1}{2}mv^2[/tex] --------1
Lets take the final speed is v' when the work done become 2W
[tex]2W=\dfrac{1}{2}mv'^2[/tex] ---------2
From above two equation
[tex]2\times \dfrac{1}{2}mv^2=\dfrac{1}{2}mv'^2[/tex]
2 v² = v'²
Therefore we can say that
[tex]v'=\sqrt{2} \ v[/tex]
The final speed become[tex] \sqrt{2}[/tex] of the initial speed .
