Suppose the length of maize ears has narrow sense heritability (h2) of 0.70. A population produces ears that have an average length of 29 cm, and from this population a breeder selects a plant producing 35-cm ears to cross by self-fertilization.Part APredict the selection differential (S) for this cross.Part BPredict the response to selection (R) for this cross.

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Answer: A is 6cm and B is 2.92

Explanation:

Selection differential is the difference between the population average and the average of the parental population

From this question population average = 29cm

Parental average = 35cm

Thus selection differential (S) = 35 - 29

S= 6

B. Response selection is given by the formula R = h2(S)

Where h2 is the narrow sense heritability and S is selection differential

Thus, R = 0.70 × 6

R = 4.2

Answer:

a) The selection differential is 6 cm

b) The response to selection is 4.2

Explanation:

please look at the solution in the attached Word file

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