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For each set of values, calculate the missing variable using the ideal gas law.

P V T n
Set 1 2.61 atm 1.69 L 36.1 °C n₁
Set 2 302 kPa 2382 mL T₂ 3.23 mol
Set 3 P₃ 0.0250 m³ 288 K 1.08 mol
Set 4 782 torr V₄ 303 K 5.26 mol

Respuesta :

Eduard22sly

Answer:

1. n = 0.174mol

2. T= 26.8K

3. P = 1.02atm

4. V = 126.88L

Explanation:

1. P= 2.61atm

V = 1.69L

T = 36.1 °C = 36.1 + 273= 309.1K

R = 0.082atm.L/mol /K

n =?

n = PV / RT = (2.61x1.69)/(0.082x309.1)

n = 0.174mol

2. P = 302 kPa = 302000Pa

101325Pa = 1atm

302000Pa = 302000/101325 = 2.98atm

V = 2382 mL = 2.382L

T =?

n = 3.23 mol

R = 0.082atm.L/mol /K

T= PV /nR = (2.98x2.382)/(3.23x0.082) = 26.8K

3. P =?

V = 0.0250 m³ = 25L

T = 288K

n = 1.08mol

R = 0.082atm.L/mol /K

P = nRT/V = (1.08x0.082x288)/25 = 1.02atm

4. P = 782 torr

760Torr = 1 atm

782 torr = 782/760 = 1.03atm

V =?

T = 303K

n = 5.26 mol

R = 0.082atm.L/mol /K

V = nRT/P

V = (5.26x0.082x303)/1.03 = 126.88L

The missing variables by using the ideal gas law is

1. n = 0.174mol

2. T= 26.8K

3. P = 1.02atm

4. V = 126.88L

Ideal gas law:

1.

Since

P= 2.61atm

V = 1.69L

T = 36.1 °C = 36.1 + 273= 309.1K

R = 0.082atm.L/mol /K

So,

n = PV / RT = (2.61x1.69)/(0.082x309.1)

n = 0.174mol

2.

Since

P = 302 kPa = 302000Pa

101325Pa = 1atm

302000Pa = 302000/101325 = 2.98atm

V = 2382 mL = 2.382L

n = 3.23 mol

R = 0.082atm.L/mol /K

So,

T= PV /nR

= (2.98x2.382)/(3.23x0.082)

= 26.8K

3.

Since

V = 0.0250 m³ = 25L

T = 288K

n = 1.08mol

R = 0.082atm.L/mol /K

So,

P = nRT/V

= (1.08x0.082x288)/25

= 1.02atm

4.

Since

P = 782 torr

760Torr = 1 atm

782 torr = 782/760 = 1.03atm

T = 303K

n = 5.26 mol

R = 0.082atm.L/mol /K

So,

V = nRT/P

V = (5.26x0.082x303)/1.03

= 126.88L

learn more about ideal gas law here: https://brainly.com/question/24649345

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