Respuesta :
Answer:
The maximum temperature of the cycle is 1065⁰R
Explanation:
The maximum temperature in degree Rankin can be obtained using the formula below;
[tex]\frac{T_2}{T_1} =[\frac{V_1}{V_2}]^{1.4-1}[/tex]
Where;
T₂ is the maximum temperature of the cycle
T₁ is the initial temperature of the cycle = 520 deg R = 520 ⁰R
V₁/V₂ is the compression ratio = 6
[tex]T_2 = T_1(\frac{V_1}{V_2})^{0.4}[/tex]
[tex]T_2=T_1(6)^{0.4}[/tex]
[tex]T_2=520^0R(6)^{0.4}[/tex]
T₂ = 1064.96 ⁰R
Therefore, the maximum temperature of the cycle is 1065⁰R
this question involves the concepts of Otto Cycle, temperature, and compression ratio.
The maximum temperature is "1064.8 °R".
Maximum temperature can be obtained using the following formula for otto cycle:
[tex]\frac{T_2}{T_1}=\frac{V_1}{V_2}^{\gamma-1}[/tex]
where,
[tex]\frac{V_1}{V_2}[/tex] = compression ratio = 6
T₁ = lower temperature = 520 °R
T₂ = maximum temperature = ?
[tex]\gamma[/tex] = ratio of specific heats = 1.4 for air
Therefore,
[tex]T_2=(520^oR)(6)^{1.4-1}[/tex]
T₂ = 1064.8 °R
learn more about otto cycle here:
https://brainly.com/question/12976213?referrer=searchResults