Answer:
[HCl] = 0.035 M
Explanation:
COMPLETE QUESTION:
What is the concentration (M) of HCl in a solution that is prepared by dissolving 25.5 g of HCl in 20.0 L of water? (Assume volume does not change after adding HCl.)
Molarity → moles of solute in 1L of solution
As we assume volume does not change after adding HCl, solution's volume is 20L
We convert solute's mass to moles → 25.5 g. 1mol / 36.45 g = 0.699 moles
Molarity (mol/L) → 0.699 mol/20L = 0.035 M
