The y-intercept of a parabola is 1, and its vertex is at (1,0). What function does the graph represent?
OA. Rx) = (x - 1)2
OB. Rx) = (x + 1)2
OC. Rx) = -1(x - 1)
OD. Rx) = -1(x + 1)2
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Answer:

A

Step-by-step explanation:

The equation of a parabola in vertex form is

y = a(x - h)² + k

where (h, k) are the coordinates of the vertex and a is a multiplier

Here (h, k) = (1, 0) , thus

y = a(x - 1)² + 0

To find a substitute the coordinates of the y- intercept (0, 1) into the equation

1 = a(- 1)² = a , thus

a = 1

y = (x - 1)² → A

Considering it's y-intercept and vertex, the equation of the parabola is given by:

[tex]y = (x - 1)^2[/tex]

What is the equation of a parabola given it’s vertex?

The equation of a quadratic function, of vertex (h,k), is given by:

[tex]y = a(x - h)^2 + k[/tex]

In which a is the leading coefficient.

In this problem, the vertex is (1,0), hence h = 1, k = 0 and:

[tex]y = a(x - 1)^2[/tex]

The y-intercept is of 1, hence, when x = 0, y = 1, so:

[tex]y = a(x - 1)^2[/tex]

[tex]1 = a(0 - 1)^2[/tex]

[tex]a = 1[/tex]

Hence, the equation is:

[tex]y = (x - 1)^2[/tex]

More can be learned about the equation of a parabola at https://brainly.com/question/24737967

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