A certain light bulb consumes 200J of electrical energy per second, but only emits 25J of light energy per second. Calculate the efficiency of this bulb.

Respuesta :

Answer:

The answer is 12.5%

Explanation:

The efficiency of a light bulb is:

Light energy comes out of the bulb / Electrical energy that was put in

= 25J / 200J = 12.5%

12.5% it told me that it had to be 20 characters long to submit it so there
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