Answer:
Step-by-step explanation:
[tex]\sqrt{x-3} +5=x\\\sqrt{x-3} =x-5\\squaring ~both~sides\\x-3=x^2-10x+25\\x^2-10x-x+25+3=0\\x^2-11x+28=0\\x^2-7x-4x+28=0\\x(x-7)-4(x-7)=0\\(x-7)(x-4)=0\\x=7,4[/tex]
put x=7 in the given equation
[tex]\sqrt{7-3} +5=7\\\sqrt{4} +5=7\\2+5=7\\7=7[/tex]
which is true .
∴ x=7 is a solution of the given eq.
now put x=4 in the given eq.
[tex]\sqrt{4-3} +5=7\\1+5=7\\6=7\\[/tex]
which is not true.
∴x=4 is an extraneous solution.
