Hollow spherical iron container with outer diameter 20 cm and thickness 0.4 cm is filled with iced water at 0C. If the outer surface temperature is 5"C, determine the approxi- mate rate of heat loss from the sphere, in kW, and the rate at which ice melts in the container. The heat from fusion of water is 333.7 kJ/kg

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Answer:

The answer is below

Explanation:

Outer diameter = Do = 20 cm = 0.2 m

Thickness = L = 0.4 cm = 0.004 m

Diameter = D =outer diameter - thickness = 0.2 - 0.004 = 0.196 m

Area = πD² = π × (0.196)² = 0.1207 m²

The thermal conductivity of iron (k) is given as 80.2 W/m.K

The heat transfer rate is given as:

ΔT = 5°C - 0°C = 5°C

h = 333.7 kJ/kg = 333.7 * 10³ J/kg

[tex]\dot{Q}=kA\frac{\Delta T}{L}=80.2*0.1207*\frac{5}{0.004} =12100=12.1\ kW[/tex]

The rate at which the ice melts is given as:

[tex]\dot{m}_{melt}=\frac{\dot{Q}}{h} =\frac{12100}{333.7*10^3}=0.036\ kg/s[/tex]

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