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If 60. liters of hydrogen gas at 546 K is cooled to 273 K at constant pressure, the new volume of the gas would be

Respuesta :

Answer:30 L

Explanation:

Initial Volume

=

V

1

=

60

l

i

t

e

r

Initial Temperature

=

T

1

=

546

K

Final Temperature

=

T

2

=

273

K

Final Vloume

=

V

2

=

?

?

Sol:-

Since the pressure is constant and the question is asking about temperature and volume, i.e,

V

1

T

1

=

V

2

T

2

V

2

=

V

1

T

2

T

1

=

60

273

546

=

60

2

=

30

l

i

t

e

r

V

2

=

30

l

i

t

e

r

Hence the new volume of the gas is

30

l

i

t

e

r

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