Respuesta :
E=hν where E is the energy of a single photon, and ν is the frequency of a single photon. We recall that a photon traveling at the speed of light c and a frequency ν will have a wavelength λ given by λ=cνλ will have an energy given by E=hcλλ=657 nm. This will be E=(6.626×10−34)(2.998×108)(657×10−9)=3.0235×10−19J
So we now know the energy of one photon of wavelength 657 nm. To find out how many photons are in a laser pulse of 0.363 Joules, we simply divide the pulse energy by the photon energy or N=Epulse Ephoton=0.3633.0235×10−19=1.2×1018So there would be 1.2×1018 photons of wavelength 657 nm in a pulse of laser light of energy 0.363 Joules.
Answer:
[tex]1.1702\times 10^{18} [/tex]photons are produced in a laser pulse of 0.497 Joules at 469 nm.
Explanation:
Energy of the laser pulse ,E'= 0.497 J
Number of photons = n
Energy of 1 photon with 469 nm wavelength = E
E' = n × E
[tex]E=\frac{hc}{\lambda }[/tex]
h = Planck's constant = [tex]6.626\times 10^{-34}Js[/tex]
c = speed of light = [tex]3\times 10^8m/s[/tex]
[tex]\lambda[/tex] = wavelength = [tex]469 nm=469\times 10^{-9}m[/tex]
[tex]1 nm=10^{-9} m[/tex]
Now put all the given values in the above formula, we get the energy of the photons.
[tex]E=\frac{6.626\times 10^{-34}Js\times 3\times 10^8m/s}{469\times 10^{-9}m}=4.2384\times 10^{-19} J[/tex]
[tex]n=\frac{E'}{E}[/tex]
[tex]n=\frac{0.496 J}{4.2384\times 10^{-19} J}=1.1702\times 10^{18} photons[/tex]
[tex]1.1702\times 10^{18} [/tex]photons are produced in a laser pulse of 0.497 Joules at 469 nm.
