Final velocity [tex]V_{f}[/tex] of the car will be 2 meters per second
Horizontal force exerted on the car will be = 200 newtons
It is given that mass= 2500 kg
Total energy =5000 j
Car distance = 25 m
So the change in KE [tex]=\dfrac{1}{2} mv_{f} ^{2} -\dfrac{1}{2} mv_{i} ^{2}[/tex]
[tex]=\dfrac{1}{2} mv_{f} ^{2}[/tex] Since [tex]V_{ i} =0[/tex]
[tex]=\dfrac{1}{2} \times2500\times v_{f} ^{2}[/tex]
[tex]5000=\dfrac{1}{2} \times2500\times v_{f} ^{2}[/tex]
[tex]V_{f} =2 \dfrac{m}{s}[/tex]
Now the Total change in energy = Work done
[tex]=F\times d[/tex]
[tex]5000= F\times 25[/tex]
[tex]F= 200 N[/tex]
Hence
Final velocity [tex]V_{f}[/tex] of the car will be 2 meters per second
Horizontal force exerted on the car will be = 200 newtons
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