Answer:
Explanation:
distance while accelerating
d = ½at² = ½(0.15)7.0² = 3.675 m
velocity at the end of 7 s
v = at = 0.15(7.0) = 1.05 m/s
distance at constant velocity
d = vt = 1.05(64) = 67.2 m
distance while decelerating
d = ut + ½at² = 1.05(2.1) + ½(-0.50)2.1² = 1.1025 m
velocity at the end of deceleration
v = u + at = 1.05 + (-0.5)2.1 = 0 m/s
total distance traveled
d = 3.675 + 67.2 + 1.1025 = 71.9775 m
rounding to the two significant figures of the question numerals
d = 72 m
that's a HUGE pharmacy.
