Respuesta :

[tex]▪▪▪▪▪▪▪▪▪▪▪▪▪  {\huge\mathfrak{Answer}}▪▪▪▪▪▪▪▪▪▪▪▪▪▪[/tex]

The Balanced chemical equation for the given reaction will be ~

[tex] \large \mathrm{\boxed{ \boxed{4\: Na + O_2} \rightarrow \boxed{ 2\;Na_2O}}}[/tex]

4,1,2

4Na + 02 —-> 2Na2O
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