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05-02-2017
Mathematics

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What are the dimensions of a rectangle that has a perimeter of 74 units and an area of 102 square units?

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wolf1728 wolf1728

05-02-2017

A) 2L + 2W = 74
B) L * W = 102

L = 102 / W then substituting this into equation A

A) 204/W + 2W = 74
A) 204 + 2W^2 = 74W
A) 2W^2 -74W + 204 = 0
W = 34 and L = 3 OR
W = 3 and L = 34

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