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This function is of the third degree so it must have three zeroes. One of them is x=6, so all you need to do is determine the zeroes for the quadratic part. You can factor it as (x+4)(x-2), and in this way you can easily see that the other two zeroes are x=-4 and x=2.
abidemiokin

The zeros of the function is 2 and -4

Function and expressions

Given the function f(x)=(x^2+2x-8)(x-6)

The zeros of the function f(x) = 0

(x^2+2x-8)(x-6) = 0

x - 6 = 0

x = 6

Also, x^2+2x-8 = 0

x^2+4x-2x-8 = 0

x(x+4)-2(x+4) = 0

(x-2)(x+4) = 0

x = 2 and -4

Hence the zeros of the function is 2 and -4

Learn more on zeros of the function here: https://brainly.com/question/11514041

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