cianahoffman405 cianahoffman405

05-07-2017
Mathematics

contestada

Use a table to compute the product below.

(10x2 - 6x + 8)(2x + 2)

A. 20x3 + 4x + 16
B. 20x3 + 8x2 + 4x + 16
C. 20x3 + 8x2 - 24x + 16
D. 20x3 + 32x2 + 4x + 16

Respuesta :

texaschic101 texaschic101

05-07-2017

(2x+2)(10x^2 - 6x + 8) =
2x(10x^2 - 6x + 8) + 2(10x^2 - 6x + 8) =
20x^3 - 12x^2 + 16x + 20x^2 - 12x + 16 =
20x^3 + 8x^2 + 4x + 16 <==

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